JEE Main Percentile Calculator 2025
Calculate your JEE Main percentile, predict your rank, and check NIT/IIIT eligibility. Based on official NTA normalization formula with detailed college recommendations.
JEE Main Percentile Calculator 2025
Calculate your JEE Main percentile, predict rank, and check college eligibility
Enter Subject-wise Performance
Physics
Chemistry
Mathematics
Understanding JEE Main Percentile System
What is JEE Main Percentile?
JEE Main percentile indicates your performance relative to other candidates. It represents the percentage of candidates who scored equal to or below your score in the exam.
Key Points:
- • Percentile ranges from 0 to 100
- • Higher percentile means better performance
- • Used for normalization across different sessions
- • Determines eligibility for NITs, IIITs, and GFTIs
Normalization Formula:
Percentile = [(Total candidates - Your rank) / Total candidates] × 100
JEE Main Scoring System
Paper Pattern
Subject-wise Distribution
Percentile to Rank Conversion
| Percentile Range | Approximate Rank | Expected Score | College Options |
|---|---|---|---|
| 99.5+ | 1-5,500 | 250+ | Top NITs all branches |
| 99.0-99.5 | 5,500-11,000 | 220-250 | Good NITs, top IIITs |
| 98.0-99.0 | 11,000-22,000 | 180-220 | Mid-tier NITs, IIITs |
| 95.0-98.0 | 22,000-55,000 | 130-180 | Lower NITs, GFTIs |
| 90.0-95.0 | 55,000-1,10,000 | 80-130 | State colleges, GFTIs |
| 80.0-90.0 | 1,10,000-2,20,000 | 40-80 | State colleges |
College Eligibility Guidelines
NITs Eligibility
- • Top NITs (Trichy, Warangal): 99.5+ percentile
- • Good NITs (Surathkal, Calicut): 98.5+ percentile
- • Mid NITs (Jaipur, Bhopal): 96+ percentile
- • Lower NITs: 90+ percentile
- • Must have 75% in Class 12th (65% for SC/ST)
IIITs Eligibility
- • Top IIITs (Hyderabad, Bangalore): 99+ percentile
- • Good IIITs (Delhi, Allahabad): 97+ percentile
- • Other IIITs: 85+ percentile
- • Class 12th requirement varies by institute
- • Some IIITs have their own counseling
GFTIs (Government Funded)
- • Indian Institute of Engineering Science and Technology
- • National Institute of Electronics and Information Technology
- • Generally require 85+ percentile
- • Participate in JoSAA counseling
State Colleges
- • Each state has different eligibility criteria
- • Generally accept 60+ percentile
- • State domicile may provide additional benefits
- • Separate counseling processes
Preparation Strategies
For 99+ Percentile
- • Master all NCERT concepts thoroughly
- • Solve previous 15 years' questions
- • Take regular mock tests (minimum 2 per week)
- • Focus on speed and accuracy
- • Analyze mistakes and weak areas
- • Practice numerical problems daily
For 90+ Percentile
- • Complete NCERT syllabus first
- • Focus on important topics with high weightage
- • Solve chapter-wise questions
- • Take weekly mock tests
- • Avoid negative marking
- • Revise formulas regularly
Frequently Asked Questions
How is JEE Main percentile calculated?
JEE Main percentile is calculated using the formula: [(Total candidates - Your rank) / Total candidates] × 100. It represents the percentage of candidates who scored equal to or below your score.
What percentile is required for NITs?
For top NITs like NIT Trichy and Warangal, you need 99.5+ percentile for popular branches like CSE. For mid-tier NITs, 95+ percentile is generally sufficient. Requirements vary by branch and category.
Can I predict my exact rank from percentile?
While percentile gives a good indication, exact rank depends on the total number of candidates and tie-breaker rules. Our calculator provides approximate rank based on previous years' data.
How many attempts are allowed for JEE Main?
You can attempt JEE Main a maximum of 6 times over 3 consecutive years after passing Class 12th. The best of all attempts is considered for admissions.